Django IntegrityError with NOT NULL Constraint

The error you're encountering (django.db.utils.IntegrityError with a NOT NULL constraint failing on the cargo field) indicates that you're trying to create a Funcionario record without providing a value for the required cargo field.

Possible Causes

1. The cargo field in your form isn't being populated correctly
2. The form data isn't being properly processed in your view
3. The cargo field in your model doesn't have a default value and is required

Troubleshooting Steps

1. Check your model definition

Make sure your model has the cargo field properly defined:

PYTHONCopied
class Funcionario(models.Model):
    # other fields...
    cargo = models.ForeignKey(Cargo, on_delete=models.CASCADE)  # or whatever relationship you have
    # other fields...

2. Verify your form

Ensure your form includes the cargo field and it's being rendered correctly:

PYTHONCopied
class FuncionarioForm(forms.ModelForm):
    class Meta:
        model = Funcionario
        fields = ['cargo', ...]  # Make sure 'cargo' is included

3. Check your view

Make sure your view is processing the form data correctly:

PYTHONCopied
def create_funcionario(request):
    if request.method == 'POST':
        form = FuncionarioForm(request.POST)
        if form.is_valid():
            form.save()
            # redirect or other logic
        else:
            print(form.errors)  # Add this to debug form validation errors
    else:
        form = FuncionarioForm()
    return render(request, 'template.html', {'form': form})

4. Check your template

Make sure your template is rendering the field correctly:

HTMLCopied
<form method="post">
    {% csrf_token %}
    {{ form.non_field_errors }}
    
    <div class="form-group">
        {{ form.cargo.errors }}
        <label for="{{ form.cargo.id_for_label }}">Cargo:</label>
        {{ form.cargo }}
    </div>
    
    <!-- Other fields -->
    
    <button type="submit">Save</button>
</form>

5. Debug with print statements

Add print statements in your view to see what data is being submitted:

PYTHONCopied
def create_funcionario(request):
    if request.method == 'POST':
        print("POST data:", request.POST)  # See what's being submitted
        # rest of your view

If you need more specific help, please share your model definition, form, view, and template code related to this functionality.