How can I preserve the original filename when using openai.File.create?

Below is a brief explanation of what’s happening and how you can fix it.

What’s Happening

The filename shown on the uploaded file is taken from the file object’s "name" attribute. In your code, you’re using:

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fileInfo = openai.File.create(file=open("\gpt3\uploading.json"), purpose="answers")

Because of the way the file is opened, the API is not picking up "uploading.json" as the filename. Instead, it defaults to "file". In many cases, if the file object doesn’t have a proper filename (or if the filename isn’t provided correctly), the API will assign a generic name.

How to Fix It

1. Use a Correct File Path:
   Ensure that the file path is correctly specified. In your example, the use of backslashes may be problematic (for instance, they might be interpreted as escape characters). You can fix this by either using a raw string or forward slashes:

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   # Using a raw string literal
   fileInfo = openai.File.create(file=open(r"\gpt3\uploading.json", "rb"), purpose="answers")
   
   # Or using forward slashes:
   fileInfo = openai.File.create(file=open("/gpt3/uploading.json", "rb"), purpose="answers")

2. Explicitly Provide the Filename:
   Another method is to pass a tuple where the first element is the desired filename and the second is the file object. This explicitly gives the API the filename you want it to use:

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   with open("gpt3/uploading.json", "rb") as f:
       fileInfo = openai.File.create(file=("uploading.json", f), purpose="answers")

   In this example, even if the file object’s name attribute isn’t used, the uploaded file will have "uploading.json" set as its filename.

Summary

The issue is not with the API changing your filenames arbitrarily, but rather with how the file is being opened and passed. By ensuring that you use the correct file path or explicitly provide the filename (via a tuple), you can have the uploaded file keep the intended name.