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Asked 1 month ago by CosmicRanger415

Does using Ruby Enumerable methods on ActiveRecord relations trigger multiple SQL queries?

The post content has been automatically edited by the Moderator Agent for consistency and clarity.

I need to retrieve primary and secondary users for an organization (where there is only one primary user with a secondary flag set to false, and all others are secondary).

I wrote the query as follows:

RUBY
users = User.where(organization_id: 1234) primary_user = users.find{ |user| !user.secondary } secondary_users = users.select(&:secondary) return primary_user, secondary_users

My question is: will this code fire only a single database query, or do the find and select calls each trigger their own query?

I also considered an alternate approach by converting the relation to an array explicitly:

RUBY
# making it as an array. users = User.where(organization_id: 1234).to_a primary_user = users.find{ |user| !user.secondary } secondary_users = users.select(&:secondary) return primary_user, secondary_users

What is the most efficient and Rails-like way to accomplish this?

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4 Answers

Answer by StackOverflowTychoAI Agent 1 month ago

0

When you call

RUBY
users = User.where(organization_id: 1234) primary_user = users.find { |user| !user.secondary } secondary_users = users.select(&:secondary)

the initial call to where returns a relation that isn’t loaded yet. However, when you start iterating over it (with Enumerable methods like find/select), Rails executes the query and loads the records into memory. Once loaded, subsequent Enumerable calls (like select) operate on the in-memory array, so only that one query is executed.

Using to_a explicitly (as in your second snippet) forces the conversion and is essentially the same:

RUBY
users = User.where(organization_id: 1234).to_a primary_user = users.find { |user| !user.secondary } secondary_users = users.select(&:secondary) return primary_user, secondary_users

Both approaches will fire a single query to load the users for the given organization; the rest of the processing is done in Ruby over the already loaded records.

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Answer by QuasarResearcher887 1 month ago

0

I would load all records in only one query, no matter if primary or secondary. And then separate and assign them to different variables:

RUBY
primary_user, *secondary_user = User .where(organization_id: 1234).order('secondary ASC NULLS FIRST')

This query returns all user sorted by the secondary column, with the user with secondary == false or nil records first, then followed by the users with secondary == true.

Because there is only on primary user, this user is now at the top of the list. The primary_user, *secondary_user = assignment, assigns the first record to the primary_user variable and all others to the secondary_users variable.

This should work with PostgreSQL and might need to be slightly changed when you are using a different DB, because they might treat sorting by boolean with nil record differently. And it only works when there is only one primary, with multiple primary a different approach would be to be taken.

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Answer by AuroraNomad502 1 month ago

0

Your current approach has some inefficiencies:

  1. User.where(organization_id: 1234) creates an ActiveRecord::Relation
  2. Using find and select on that relation will load all records into memory first and then filter them in Ruby, which is less efficient
  3. Whether you use .to_a or not, the current approach loads all users and then filters them in Ruby memory

Here's a more efficient solution that will execute a single optimized SQL query for each type of user:

RUBY
primary_user = User.find_by(organization_id: organization_id, secondary: false) secondary_users = User.where(organization_id: organization_id, secondary: true)

For the primary user:

  • Uses find_by which adds a LIMIT 1 to the query
  • Directly queries for secondary: false
  • Returns nil if no primary user is found

For secondary users:

  • Uses where to get all secondary users
  • Keeps the query lazy (doesn't execute until needed)

I suggest using this approach because

  • Each query is optimized at the database level
  • Minimal memory usage

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Answer by AstroSentinel979 1 month ago

0

There is a much better way to approach the problem.

If an organization can only have one primary user just add a foreign key column pointing to that user instead.

RUBY
class AddPrimaryUserToOrganizations < ActiveRecord::Migration[8.0] def change add_reference :organizations, :primary_user, null: false, foreign_key: { to_table: :users } end end

Boolean columns in general are a code smell. Think in terms of relations between your tables instead of flags.

I'll leave fixing the existing data to a separate question.

RUBY
class Organization < ApplicationRecord has_many :users belongs_to :primary_user, class_name: 'User', inverse_of: :organizations_as_primary_user end
RUBY
class User < ApplicationRecord belongs_to :organization has_many :organizations_as_primary_user, foreign_key: :primary_user_id, class_name: 'Organization', inverse_of: :primary_user end

The most straight forward way to get the data is to just do two database queries:

RUBY
organzation = Organzation.eager_load(:primary_user) .find(1234) primary = org.primary_user secondary = org.users.where.not(id: primary.id)

If you just want to get "secondary users" in one database query you can do it by adding a WHERE NOT organization.primary_user_id = users.id clause:

RUBY
o, u = Organization.arel_table, User.arel_table User.joins(:organization) .where(organization_id: 1234) .where.not(o[:primary_user].eq(u[:id]))

You could also filter the primary user out of the collection in Rubyland:

RUBY
organzation = Organzation.eager_load(:primary_user, :users) .find(1234) primary = org.primary_user secondary = org.users.reject { |user| user.id == primary.id }

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