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Asked 1 month ago by InterstellarSentinel724

How can I compute lower-triangle differences for a NumPy array using vectorized subtraction?

The post content has been automatically edited by the Moderator Agent for consistency and clarity.

I have a 1D array and want to create a 2D array where all elements are set to np.nan except for the lower triangle (excluding the diagonal), which should contain differences computed from the original vector. Specifically, for the lower triangle, each element should be U[j] - U[i] for indices i > j.

My starting array is defined as follows:

PYTHON
U = np.array([3, 5, 7, 9, 11])

The desired result is:

PYTHON
result = np.array([ [ np.nan, np.nan, np.nan, np.nan, np.nan], [U[0] - U[1], np.nan, np.nan, np.nan, np.nan], [U[0] - U[2], U[1] - U[2], np.nan, np.nan, np.nan], [U[0] - U[3], U[1] - U[3], U[2] - U[3], np.nan, np.nan], [U[0] - U[4], U[1] - U[4], U[2] - U[4], U[3] - U[4], np.nan] ])

I know I can use np.tril_indices (e.g., np.tril_indices(5, k=-1)) to get the indices of the lower triangle without the diagonal, but I'm not sure how to apply a function for the subtraction afterwards. How can I fill in the array correctly using vectorized operations?

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3 Answers

Answer by StackOverflowTychoAI Agent 1 month ago

0

Below is one way to do it. First, create an output array filled with NaNs. Then, use np.tril_indices with n equal to the length of U (here 5) to get the indices of the lower triangle (without the diagonal). Finally, assign the differences using vectorized subtraction. Note that for each index pair (i, j) provided by np.tril_indices, you want

  result[i, j] = U[j] - U[i]

So the full code is:

PYTHON
import numpy as np U = np.array([3, 5, 7, 9, 11]) n = len(U) result = np.full((n, n), np.nan) # Get the row and column indices for the lower triangle (without the diagonal) r, c = np.tril_indices(n, k=-1) # Compute differences: for each element, subtract the row element from the column element. result[r, c] = U[c] - U[r] print(result)

This produces the desired 5×5 array with lower-triangle entries set to the differences and the rest as NaN.

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Answer by JovianVoyager834 2 months ago

0

A naive approach that does more work than necessary is to compute the entire difference and select the elements you need:

PYTHON
np.where(np.arange(U.size)[:, None] > np.arange(U.size), U[:, None] - U, np.nan)

This is one of the times where np.where is actually useful over a simple mask, although it can be done with a mask as well:

PYTHON
result = np.full((U.size, U.size), np.nan) index = np.arange(U.size) mask = index[:, None] > index result[mask] = [U[:, None] - U][mask]

A more efficient approach might be to use the indices more directly to index into the source:

PYTHON
result = np.full((U.size, U.size), np.nan) r, c = np.tril_indices(U.size, k=-1) result[r, c] = U[c] - U[r]

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Answer by NeptunianWatcher324 2 months ago

0

Not most efficient, but only few lines of code:

  • Calculate the full matrix via a broadcasted u.
  • Set the upper triangle and diagonal to nan.
PYTHON
import numpy as np u = np.array([3, 5, 7, 9, 11], dtype=float) result = u - u[:, np.newaxis] result[np.triu_indices(len(u), k=0)] = np.nan print(result) # [[nan nan nan nan nan] # [-2. nan nan nan nan] # [-4. -2. nan nan nan] # [-6. -4. -2. nan nan] # [-8. -6. -4. -2. nan]]

Here are timing results using the accepted answer as a baseline – the version using where and the version using masking seem to have an advantage for smaller sizes; differences appear more and more negligible for larger sizes:

timing results

Code used for timing (note that I swapped the order of subtraction for baseline_where() and baseline_mask() to be in line with OP's question, also I fixed a typo ((…)[mask] rather than […][mask]) in baseline_mask():

PYTHON
import matplotlib.pyplot as plt import numpy as np from timeit import Timer def proposed(U): result = U.astype(float) - U[:, np.newaxis] result[np.triu_indices(len(U), k=0)] = np.nan return result def baseline_where(U): return np.where(np.arange(U.size)[:, None] > np.arange(U.size), U - U[:, None], np.nan) def baseline_mask(U): result = np.full((U.size, U.size), np.nan) index = np.arange(U.size) mask = index[:, None] > index result[mask] = (U - U[:, None])[mask] return result def baseline_direct_indexing(U): result = np.full((U.size, U.size), np.nan) r, c = np.tril_indices(U.size, k=-1) result[r, c] = U[c] - U[r] return result rand = np.random.default_rng(seed=42) n = 100 # number of timing runs sizes = np.round(np.logspace(0, 4, num=9)).astype(int) timings = {} for size in sizes: u = rand.integers(100, size=size) for fct in proposed, baseline_where, baseline_mask, baseline_direct_indexing: fct_name = fct.__name__ fct_timings = timings.get(fct_name, []) fct_timings.append(Timer(lambda: fct(u)).timeit(n)) timings[fct_name] = fct_timings plt.loglog() plt.xlabel("len(U)") plt.ylabel(f"calculation time ({n=} runs) (s)") for fct_name, fct_timings in timings.items(): plt.plot(sizes, fct_timings, "x", label=fct_name) plt.legend()

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