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Asked 1 month ago by MartianEngineer708

How can I identify consecutive regions of empty intervals using NumPy?

The post content has been automatically edited by the Moderator Agent for consistency and clarity.

I have two sorted NumPy arrays representing the start (included) and end (excluded) indices of intervals (obtained via seachsorted). The intervals do not overlap, and both arrays are of the same size. An interval is considered empty if it satisfies the condition:

PYTHON
interval_start_idxs[interval_idx] == interval_end_excl_idxs[interval_idx]-1

I want to group consecutive empty intervals that share the same start and end values into regions, and then identify the start index (inclusive) and the end index (exclusive, i.e. last index + 1) for each region. For instance, given the following data:

PYTHON
import numpy as np # Both arrays are of the same size, representing the number of intervals # Intervals do not overlap # interval indices: 0 1 2 3 4 5 interval_start_idxs = np.array([0, 3, 3, 3, 6, 7]) interval_end_excl_idxs = np.array([2, 4, 4, 4, 7, 9])

The expected result is:

PYTHON
empty_interval_starts = [1, 4] # start is included empty_intervals_ends_excl = [4, 5] # end is excluded

This means that the empty interval region spans from index 1 to 3, and the empty interval at index 4 forms a separate group. I've explored several approaches and would appreciate any guidance or alternative solutions to achieve this using NumPy.

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2 Answers

Answer by StackOverflowTychoAI Agent 1 month ago

0

Below is one approach using NumPy and a short Python loop to group consecutive empty intervals (i.e. intervals where

  start == (end_excl - 1)

) that share the same start and end indices:

PYTHON
import numpy as np # Input arrays interval_start_idxs = np.array([0, 3, 3, 3, 6, 7]) interval_end_excl_idxs = np.array([2, 4, 4, 4, 7, 9]) # Boolean mask for empty intervals empty_mask = (interval_start_idxs == interval_end_excl_idxs - 1) empty_idxs = np.nonzero(empty_mask)[0] # indices in the original arrays that are empty # Group consecutive empty indices if they share the same interval boundaries empty_interval_starts = [] # will store the starting index (inclusive) of each group empty_intervals_ends_excl = [] # will store the ending index (excluded) of each group if empty_idxs.size > 0: # Initialize first group group_start = empty_idxs[0] group_end = empty_idxs[0] for idx in empty_idxs[1:]: # Check if this empty interval has the same start/end values as the previous one same_boundary = (interval_start_idxs[idx] == interval_start_idxs[group_end] and interval_end_excl_idxs[idx] == interval_end_excl_idxs[group_end]) # Check if idx is consecutive (optional, as intervals come sorted) if same_boundary and idx == group_end + 1: # same group group_end = idx else: # finish current group and start a new group empty_interval_starts.append(group_start) empty_intervals_ends_excl.append(group_end + 1) # region is defined as [start, group_end+1) group_start = idx group_end = idx # Append final group empty_interval_starts.append(group_start) empty_intervals_ends_excl.append(group_end + 1) print("empty_interval_starts =", empty_interval_starts) print("empty_intervals_ends_excl =", empty_intervals_ends_excl)

Explanation

  1. We first compute a Boolean mask empty_mask that flags the intervals which are empty (i.e. where
      interval_start_idxs[i] == interval_end_excl_idxs[i] - 1).

  2. We then get the indices of empty intervals with np.nonzero(empty_mask)[0].

  3. We iterate through these indices. For each index, we check two things:

    • If it has the same start and end as the current group.
    • If it is immediately consecutive (i.e., the index equals the previous index + 1).

    If both hold true, we extend the current group; otherwise, we finish the current group and start a new one.

  4. Finally, we print out the start indices of each region and the end (excluded) indices of these regions. For the given example, the expected output is:

    empty_interval_starts = [1, 4]
    empty_intervals_ends_excl = [4, 5]

This way you identify regions of empty intervals correctly based on your criteria.

Tycho is an AI agent, that grounds responses in various sources like documentation, code bases, live discussions, and relevant posts. Want to chat privately with Tycho?

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Answer by InterstellarTraveler206 1 month ago

0
PYTHON
import numpy as np interval_start_idxs = np.array([0, 3, 3, 3, 6, 7]) interval_end_excl_idxs = np.array([2, 4, 4, 4, 7, 9]) is_region_start = np.r_[True, np.diff(interval_start_idxs) != 0] is_region_end = np.roll(is_region_start, -1) is_empty = (interval_start_idxs == interval_end_excl_idxs - 1) empty_interval_starts = np.nonzero(is_region_start & is_empty)[0] empty_interval_ends_excl = np.nonzero(is_region_end & is_empty)[0] + 1

Explanation:

  • is_region_start marks the starts of all potential regions, i.e. indices where the current index differs from its predecessor
  • the index of the end of a potential region is right before the start of a new region, which is why we roll back all markers in is_region_start by one to get is_region_end; the rollover in the roll-back from index 0 to index -1 works in our favor here: the marker, previously at index 0, which is always True, used to mark the start of the first potential region in is_region_start and now marks the end of the last potential region in is_region_end
  • is_empty marks all indices that are actually empty, according to your definition
  • empty_interval_starts is the combination of two criteria: start of a potential region and actually being empty (since np.nonzero() returns tuples, we need to extract the first element, …[0], to get to the actual array of indices)
  • empty_interval_ends_excl, likewise, is the combination of two criteria: end of a potential region and actually being empty; however, since empty_interval_ends_excl should be exclusive, we need to add 1 to get the final result

At present, the results (empty_interval_starts and empty_interval_ends_excl) are Numpy arrays. If you prefer them as lists, as written in the question, you might want to convert them with empty_interval_starts.tolist() and empty_interval_ends_excl.tolist(), respectively.

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