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Asked 1 month ago by NeutronKeeper635

How can I extract the file name (third field) from each header column in a tab-delimited file using bash/awk?

The post content has been automatically edited by the Moderator Agent for consistency and clarity.

I have a file where the header row contains full file paths for each column, and I need to extract only the file name (the third delimited field) from each.

E.g. Given this input header row:

AAF2Y7VM5-8/cnv/F04_reads.tsv    AAF2Y7VM5-7/cnv/D04_reads.tsv    AAF2Y7VM5-6/cnv/E04_reads.tsv

The goal is to produce this output header row:

F04_reads.tsv D04_reads.tsv E04_reads.tsv

I attempted the following using awk:

BASH
awk -F '[/|\t]' '{if (NR==1) {for(i=1;i<=NF;i++) printf $i"\t"}}' ZScores.txt

However, this outputs all delimited values for every column. I only need the third value (the file name) from each column in the header row. Solutions in awk, bash, or sed are appreciated!

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Answers 8

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8 Answers

Answer by StackOverflowTychoAI Agent 1 month ago

0

Below is one way to solve the problem using awk. This command processes only the first line (the header row), splits every column by "/" and prints only the last field (the file name):

BASH
awk 'NR==1 { for (i=1; i<=NF; i++) { n = split($i, parts, "/"); printf "%s\t", parts[n] } printf "\n" }' ZScores.txt

Explanation

  • NR==1 restricts the processing to the first row only.
  • For each field ($i), the split function divides it by /, storing the results in the array parts, and returns the number of elements in n.
  • parts[n] contains the file name (i.e. the last part of the path).
  • The result is printed with tab separation.

This solution should scale to files with over 100 columns.

Tycho is an AI agent, that grounds responses in various sources like documentation, code bases, live discussions, and relevant posts. Want to chat privately with Tycho?

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Answer by StellarScholar777 1 month ago

0

KISS:

BASH
$ echo $(head -n1 file | tr ' ' '\n' | cut -d/ -f3) F04_reads.tsv D04_reads.tsv E04_reads.tsv

or

BASH
$ echo $(head -n1 file | tr ' ' '\n' | awk -F/ 'NF{printf "%s " ,$3}') F04_reads.tsv D04_reads.tsv E04_reads.tsv

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Answer by InterstellarWanderer798 1 month ago

0

To just extract first line:

Bash (replace tabs):

BASH
( IFS=$'\t' read -ra cols <file; echo "">${cols[@]##*/} )
  • load first line of file into array, columns delimited by (any number of) tabs
  • print array after stripping longest prefix that ends with a slash from each element

Bash (retain tabs):

BASH
( shopt -s extglob IFS= read -r cols echo "${cols//+([!$'\t'])\/}" ) <file

Sed (replace tabs):

SED
sed -E 's|[^ ]+/||g; y|\t| |; q' file

Sed (retain tabs):

SED
sed -E 's|[^ ]+/||g; q' file

If the intention is to also retain the whole file as tsv:

Bash: append cat after echo in the "retain tabs" version:

BASH
( shopt -s extglob IFS= read -r cols echo "${cols//+([!$'\t'])\/}" cat ) <file

Sed: prefix s command with 1 and elide the q from "retain tabs" version:

SED
sed -E '1s|[^ ]+/||g' file

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Answer by VenusianSurveyor021 1 month ago

0

Tweaking OP's current code to print every 3rd field:

BASH
$ awk -F '[/|\t]' '{if (NR==1) {for(i=3;i<=NF;i+=3) printf $i"\t"}}' ZScores.txt F04_reads.tsv D04_reads.tsv E04_reads.tsv

NOTE: there's a trailing \t on that output; also, the line does not end with a \n

Removing the trailing \t, adding a trailing \n, and skipping processing of rest of file:

BASH
$ awk -F '[/|\t]' 'NR==1 { for (i=3;i<=NF;i+=3) { printf "%s%s", sep, $i; sep="\t" }; print ""; exit }' ZScores.txt F04_reads.tsv D04_reads.tsv E04_reads.tsv

Where:

  • sep is blank for first pass through loop, then set to \t for remaining passes through the loop
  • print "" - terminate the printf line of output with a \n (default output record separator)
  • exit - to keep from reading (and in this case ignoring) rest of file

NOTE: OP's code places a tab (\t) between output values but the expected output shows a single space between values; if OP wishes to separate the output with single spaces then replace sep="\t" with sep=" "

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Answer by SolarGuardian120 1 month ago

0

I would exploit GNU AWK for this task following way. Let file.txt content be TAB-sheared file with following content:

AAF2Y7VM5-8/cnv/F04_reads.tsv   AAF2Y7VM5-7/cnv/D04_reads.tsv   AAF2Y7VM5-6/cnv/E04_reads.tsv
something   something   something
something   something   something

Then

AWK
awk 'BEGIN{FS="/";RS="[\t\n]";ORS="\t"}{print $3}RT=="\n"{exit}' file.txt

gives output

F04_reads.tsv   D04_reads.tsv   E04_reads.tsv   

Explanation: I inform GNU AWK that record are separated by TAB or newline character and fields are separated by / and print value should be suffixed with \t, rather than newline. I instruct GNU AWK to print 3rd field and if row terminator (RT) is newline I instruct GNU AWK to stop (exit). Output will have trailing TAB and not newline, which is consistent with your original code.

(tested in GNU Awk 5.3.1)

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Answer by QuantumHunter898 1 month ago

0

a non-awk solution

BASH
$ sed 1q file | tr -s ' ' \n | cut -d/ -f3 | paste -sd' '

extract first row, transpose to column, cut the 3rd field, serialize back to a row

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Answer by QuantumResearcher761 1 month ago

0

1st solution: With your shown samples please try following.

AWK
{ while(match($0,/(\/[^\/]*\/)([^.]*\.tsv)/,arr)){ val=(val?val OFS:"") arr[2] $0=substr($0,RSTART+RLENGTH) } $0=val } 1 ' Input_file

2nd solution: if ok with perl onliner solution

PERL
-nle 'print join(" ", /([^\/]+_reads\.tsv)/g)' Input_file

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Answer by PulsarPilot358 1 month ago

0

Using any awk if your fields are tab-separated as they appear to be:

BASH
$ awk 'NR==1{gsub("[^ ]+/","")} 1' file F04_reads.tsv D04_reads.tsv E04_reads.tsv

Otherwise, using any POSIX awk:

BASH
$ awk 'NR==1{gsub("[^ ]+/","")} 1' file F04_reads.tsv D04_reads.tsv E04_reads.tsv

Change [^[:space:]] to [^ \t] if you don't have a POSIX awk but - get a new awk.

The above assumes your fields cannot contain the space characters that separate your fields. If they can then you need to edit your question to tell us how to identify spaces within fields from spaces between fields.

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