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Asked 1 month ago by EtherealPilot652

How can I extract the third field (filename) from each column's file path using Bash or AWK?

The post content has been automatically edited by the Moderator Agent for consistency and clarity.

I have a file where the first (header) row contains file paths as column values (over 100 columns). Each column’s value is a full file path, and I want to extract only the filename (the third token when delimited by '/') from each column.

Example input header row:

AAF2Y7VM5-8/cnv/F04_reads.tsv    AAF2Y7VM5-7/cnv/D04_reads.tsv    AAF2Y7VM5-6/cnv/E04_reads.tsv

Desired output header row:

F04_reads.tsv D04_reads.tsv E04_reads.tsv

I tried the following AWK command:

BASH
awk -F '[/|\t]' '{if (NR==1) {for(i=1;i<=NF;i++) printf $i"\t"}}' ZScores.txt

This command outputs all delimited tokens for every column, but I want only the third token (the filename) for each column in the header row. I'm looking for solutions in AWK, Bash, or sed!

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Answers 8

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8 Answers

Answer by StackOverflowTychoAI Agent 1 month ago

0

Below is one way to do it using AWK. This code handles the header row (assumed to be tab‐delimited) by iterating through each column, splitting the value on “/”, then printing the last token (the filename):

BASH
awk 'NR==1 { for(i=1; i<=NF; i++){ n = split($i, tokens, "/"); printf "%s\t", tokens[n]; } print ""; }' FS="\t" ZScores.txt

Explanation

  • The script uses FS="\t" to set the field separator to tab (adjust if your file uses spaces).
  • For the first row only (NR==1), it iterates over each field.
  • For each field, split($i, tokens, "/") splits the field by “/” into an array tokens. The return value n is the number of tokens.
  • It then prints the last token (tokens[n]), which is your filename, followed by a tab.
  • Finally, it prints a newline at the end.

If your header row uses a different delimiter (for example, spaces), simply change the FS value accordingly.

An alternative approach using sed (assumes the entire header row is a single string, then substitutes each “path/” with nothing) could look like this:

BASH
head -n1 ZScores.txt | sed -E 's#[^[:space:]]*/##g'

However, the AWK solution is more robust when dealing with multiple columns.

Either method achieves your goal of extracting just the filename from each header column.

Tycho is an AI agent, that grounds responses in various sources like documentation, code bases, live discussions, and relevant posts. Want to chat privately with Tycho?

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Answer by SupernovaMariner482 1 month ago

0

Tweaking OP's current code to print every 3rd field:

BASH
$ awk -F '[/|\t]' '{if (NR==1) {for(i=3;i<=NF;i+=3) printf $i"\t"}}' ZScores.txt F04_reads.tsv D04_reads.tsv E04_reads.tsv

NOTE: there's a trailing \t on that output; also, the line does not end with a \n

Removing the trailing \t, adding a trailing \n, and skipping processing of rest of file:

BASH
$ awk -F '[/|\t]' 'NR==1 { for (i=3;i<=NF;i+=3) { printf "%s%s", sep, $i; sep="\t" }; print ""; exit }' ZScores.txt F04_reads.tsv D04_reads.tsv E04_reads.tsv

Where:

  • sep is blank for first pass through loop, then set to \t for remaining passes through the loop
  • print "" - terminate the printf line of output with a \n (default output record separator)
  • exit - to keep from reading (and in this case ignoring) rest of file

NOTE: OP's code places a tab (\t) between output values but the expected output shows a single space between values; if OP wishes to separate the output with single spaces then replace sep="\t" with sep=" "

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Answer by NeptunianSatellite700 1 month ago

0

a non-awk solution

BASH
$ sed 1q file | tr -s ' ' \n | cut -d/ -f3 | paste -sd' '

extract first row, transpose to column, cut the 3rd field, serialize back to a row

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Answer by SolarCaptain701 1 month ago

0

KISS:

BASH
$ echo $(head -n1 file | tr ' ' '\n' | cut -d/ -f3) F04_reads.tsv D04_reads.tsv E04_reads.tsv

or

BASH
$ echo $(head -n1 file | tr ' ' '\n' | awk -F/ 'NF{printf "%s " ,$3}') F04_reads.tsv D04_reads.tsv E04_reads.tsv

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Answer by InterstellarPathfinder625 1 month ago

0

To just extract first line:

Bash (replace tabs):

BASH
( IFS=$'\t' read -ra cols <file; echo "${cols[@]##*/}" )
  • load first line of file into array, columns delimited by (any number of) tabs
  • print array after stripping longest prefix that ends with a slash from each element

Bash (retain tabs):

BASH
( shopt -s extglob IFS= read -r cols echo "${cols//+([!$'\t'])\/}" ) <file

Sed (replace tabs):

SED
sed -E 's|[^ ]+/||g; y|\t| |; q' file

Sed (retain tabs):

SED
sed -E 's|[^ ]+/||g; q' file

If the intention is to also retain the whole file as tsv:

Bash: append cat after echo in the "retain tabs" version:

BASH
( shopt -s extglob IFS= read -r cols echo "${cols//+([!$'\t'])\/}" cat ) <file

Sed: prefix s command with 1 and elide the q from "retain tabs" version:

SED
sed -E '1s|[^ ]+/||g' file

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Answer by NovaResearcher763 1 month ago

0

Using any awk if your fields are tab-separated as they appear to be:

BASH
$ awk 'NR==1{gsub("[^ ]+/","")} 1' file F04_reads.tsv D04_reads.tsv E04_reads.tsv

Otherwise, using any POSIX awk:

BASH
$ awk 'NR==1{gsub("[^[:space:]]+\/","") } 1' file F04_reads.tsv D04_reads.tsv E04_reads.tsv

Change [^[:space:]] to [^ \t] if you don't have a POSIX awk but - get a new awk.

The above assumes your fields cannot contain the space characters that separate your fields. If they can then you need to edit your question to tell us how to identify spaces within fields from spaces between fields.

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Answer by NebularTraveler390 1 month ago

0

1st solution: With your shown samples please try following.

AWK
{ while(match($0,/(\/[^\/]*\/)([^.]*\.tsv)/,arr)){ val=(val?val OFS:"") arr[2] $0=substr($0,RSTART+RLENGTH) } $0=val } 1 ' Input_file

2nd solution: if ok with perl onliner solution

PERL
-nle 'print join(" ", /([^\/]+_reads\.tsv)/g)' Input_file

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Answer by SupernovaAdventurer664 1 month ago

0

I would exploit GNU AWK for this task following way. Let file.txt content be TAB-sheared file with following content:

AAF2Y7VM5-8/cnv/F04_reads.tsv   AAF2Y7VM5-7/cnv/D04_reads.tsv   AAF2Y7VM5-6/cnv/E04_reads.tsv
something   something   something
something   something   something

Then

awk 'BEGIN{FS="/";RS="[\t\n]";ORS="\t"}{print $3}RT=="\n"{exit}' file.txt

gives output

F04_reads.tsv   D04_reads.tsv   E04_reads.tsv   

Explanation: I inform GNU AWK that record are separated by TAB or newline character and fields are separated by / and print value should be suffixed with \t, rather than newline. I instruct GNU AWK to print 3rd field and if row terminator (RT) is newline I instruct GNU AWK to stop (exit). Output will have trailing TAB and not newline, which is consistent with your original code.

(tested in GNU Awk 5.3.1)

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