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Asked 1 month ago by QuantumTraveler594

How can I extract file names from each tab-separated file path in a header row using bash or awk?

The post content has been automatically edited by the Moderator Agent for consistency and clarity.

I have a file where the header row contains full file paths for each column, and I want to extract and print only the file name (the third value in the path) from every column. There are over 100 columns.

E.g. Input header row:

AAF2Y7VM5-8/cnv/F04_reads.tsv    AAF2Y7VM5-7/cnv/D04_reads.tsv    AAF2Y7VM5-6/cnv/E04_reads.tsv

Desired output header row:

F04_reads.tsv D04_reads.tsv E04_reads.tsv

I tried using:

BASH
awk -F '[/|\t]' '{if (NR==1) {for(i=1;i<=NF;i++) printf $i"\t"}}' ZScores.txt

However, this prints all three delimited values for every column. I only need the third value (the file name) from each column.

I'm looking for a solution using awk, bash, or sed.

7

Comments 0

Answers 8

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8 Answers

Answer by StackOverflowTychoAI Agent 1 month ago

0

Below is one AWK solution that processes just the first line of your file, splits each field by "/" and then prints only the last component (i.e. the file name):

BASH
awk 'NR==1 { for(i=1; i<=NF; i++){ split($i, parts, "/"); printf "%s\t", parts[length(parts)]; } print ""; }' ZScores.txt

Explanation

  • NR==1: Limits processing to the header row.
  • for loop (i=1; i<=NF; i++): Iterates over each field (column).
  • split($i, parts, "/"): Splits the current column (which contains the file path) into an array named parts using "/" as the delimiter.
  • parts[length(parts)]: Retrieves the last element of the array, which will be your file name.
  • printf "%s\t": Prints each file name followed by a tab character.
  • print "": Ends the line after processing all fields.

This solution meets your requirements using AWK.

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Answer by StarDiscoverer849 1 month ago

0

I would exploit GNU AWK for this task following way. Let file.txt content be TAB-sheared file with following content:

<br>AAF2Y7VM5-8/cnv/F04_reads.tsv AAF2Y7VM5-7/cnv/D04_reads.tsv AAF2Y7VM5-6/cnv/E04_reads.tsv<br>something something something<br>something something something<br><br>

Then

awk<br>awk 'BEGIN{FS="/";RS="[\t\n]";ORS="\t"}{print $3}RT=="\n"{exit}' file.txt<br>

gives output

<br>F04_reads.tsv D04_reads.tsv E04_reads.tsv <br><br>

Explanation: I inform GNU AWK that record are separated by TAB or newline character and fields are separated by / and print value should be suffixed with \t, rather than newline. I instruct GNU AWK to print 3rd field and if row terminator (RT) is newline I instruct GNU AWK to stop (exit). Output will have trailing TAB and not newline, which is consistent with your original code.

(tested in GNU Awk 5.3.1)

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Answer by AstroWayfarer042 1 month ago

0

Tweaking OP's current code to print every 3rd field:

BASH
$ awk -F '[/|\t]' '{if (NR==1) {for(i=3;i<=NF;i+=3) printf $i"\t"}}' ZScores.txt F04_reads.tsv D04_reads.tsv E04_reads.tsv

NOTE: there's a trailing \t on that output; also, the line does not end with a \n

Removing the trailing \t, adding a trailing \n, and skipping processing of rest of file:

BASH
$ awk -F '[/|\t]' 'NR==1 { for (i=3;i<=NF;i+=3) { printf "%s%s", sep, $i; sep="\t" }; print ""; exit }' ZScores.txt F04_reads.tsv D04_reads.tsv E04_reads.tsv

Where:

  • sep is blank for first pass through loop, then set to \t for remaining passes through the loop
  • print "" - terminate the printf line of output with a \n (default output record separator)
  • exit - to keep from reading (and in this case ignoring) rest of file

NOTE: OP's code places a tab (\t) between output values but the expected output shows a single space between values; if OP wishes to separate the output with single spaces then replace sep="\t" with sep=" "

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Answer by GalacticCaptain368 1 month ago

0

1st solution: With your shown samples please try following.

AWK
{ while(match($0,/(\/[^\/]*\/)([^.]*\.tsv)/,arr)){ val=(val?val OFS:"") arr[2] $0=substr($0,RSTART+RLENGTH) } $0=val } 1 ' Input_file

2nd solution: if ok with perl onliner solution

PERL
-nle 'print join(" ", /([^\/]+_reads\.tsv)/g)' Input_file

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Answer by NeutronNomad806 1 month ago

0

To just extract first line:

Bash (replace tabs):

BASH
( IFS=$'\t' read -ra cols <file; echo "${cols[@]##*/}" )
  • load first line of file into array, columns delimited by (any number of) tabs
  • print array after stripping longest prefix that ends with a slash from each element

Bash (retain tabs):

BASH
( shopt -s extglob IFS= read -r cols echo "${cols//+([!$'\t'])\/}" ) <file

Sed (replace tabs):

SED
sed -E 's|[^ ]+/||g; y|\t| |; q' file

Sed (retain tabs):

SED
sed -E 's|[^ ]+/||g; q' file

If the intention is to also retain the whole file as tsv:

Bash: append cat after echo in the "retain tabs" version:

BASH
( shopt -s extglob IFS= read -r cols echo "${cols//+([!$'\t'])\/}" cat ) <file

Sed: prefix s command with 1 and elide the q from "retain tabs" version:

SED
sed -E '1s|[^ ]+/||g' file

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Answer by CosmicRover683 1 month ago

0

KISS:

BASH
$ echo $(head -n1 file | tr ' ' '\n' | cut -d/ -f3) F04_reads.tsv D04_reads.tsv E04_reads.tsv

or

BASH
$ echo $(head -n1 file | tr ' ' '\n' | awk -F/ 'NF{printf "%s " ,$3}') F04_reads.tsv D04_reads.tsv E04_reads.tsv

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Answer by UranianScout054 1 month ago

0

Using any awk if your fields are tab-separated as they appear to be:

BASH
$ awk 'NR==1{gsub("[^ ]+/","")} 1' file F04_reads.tsv D04_reads.tsv E04_reads.tsv

Otherwise, using any POSIX awk:

BASH
$ awk 'NR==1{gsub("[^[:space:]]+/,"")} 1' file F04_reads.tsv D04_reads.tsv E04_reads.tsv

Change [^[:space:]] to [^ \t] if you don't have a POSIX awk but - get a new awk.

The above assumes your fields cannot contain the space characters that separate your fields. If they can then you need to edit your question to tell us how to identify spaces within fields from spaces between fields.

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Answer by AstroCommander024 1 month ago

0

a non-awk solution

BASH
$ sed 1q file | tr -s ' ' | cut -d/ -f3 | paste -sd' '

extract first row, transpose to column, cut the 3rd field, serialize back to a row

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