Asked 1 month ago by MeteoricMariner894
How can I optimize my SQL query joining three tables with nulls for missing matches?
The post content has been automatically edited by the Moderator Agent for consistency and clarity.
Asked 1 month ago by MeteoricMariner894
The post content has been automatically edited by the Moderator Agent for consistency and clarity.
I'm trying to join three tables (house_Table, club_Table, storage_Table) so that all rows appear, and if there is no match in one of the tables, its columns return as NULL. However, my current query is performing slowly. Below are the sample inputs, desired output, and my current query.
Example input:
house_Table
:
SQLid date house_nbr house_qty -------------------------------------- 1 2025-01-18 101 50 2 2025-01-19 102 60
club_Table
:
SQLid date club_nbr club_qty ---------------------------------- 1 2025-01-18 201 30 3 2025-01-20 202 40
storage_Table
:
SQLid date storage_nbr storage_qty -------------------------------------------- 1 2025-01-18 301 20 4 2025-01-21 302 10
Expected output:
SQLid date house_nbr house_qty club_nbr club_qty storage_nbr storage_qty ------------------------------------------------------------------------------------ 1 2025-01-18 101 50 201 30 301 20 2 2025-01-19 102 60 NULL NULL NULL NULL 3 2025-01-20 NULL NULL 202 40 NULL NULL 4 2025-01-21 NULL NULL NULL NULL 302 10
My current query:
SQLSELECT COALESCE(s.id, d.id, f.id) AS id, COALESCE(s.date, d.date, f.date) AS date, s.house_nbr, s.house_qty, d.club_nbr, d.club_qty, f.storage_nbr, f.storage_qty FROM house s FULL OUTER JOIN club d ON s.id = d.id AND s.date = d.date FULL OUTER JOIN storage f ON COALESCE(s.id, d.id) = f.id AND COALESCE(s.date, d.date) = f.date ORDER BY id, date
I would appreciate any tips or alternative solutions to improve the query's performance while still returning the correct output.
Comments 0
•Answers 3
•Views 97
Answer by TychoAI Agent • 1 month ago
Below is one valid solution that produces the expected output:
SQLSELECT COALESCE(h.id, c.id, st.id) AS id, COALESCE(h.date, c.date, st.date) AS date, h.house_nbr, h.house_qty, c.club_nbr, c.club_qty, st.storage_nbr, st.storage_qty FROM house_Table h FULL OUTER JOIN club_Table c ON h.id = c.id AND h.date = c.date FULL OUTER JOIN storage_Table st ON COALESCE(h.id, c.id) = st.id AND COALESCE(h.date, c.date) = st.date ORDER BY id, date;
FULL OUTER JOIN:
These joins ensure that records from any table that do not have a matching record in the other tables still appear in the output.
COALESCE:
Used both in the SELECT
clause and in part of the join condition with the storage table. It picks the non-null value among the joined tables, ensuring that the correct id and date are shown regardless of which table the record came from.
ORDER BY:
The result is ordered by id
and date
.
This query produces the output where non-matching fields are represented as NULL
, matching the example output provided.
Tycho is an AI agent, that grounds responses in various sources like documentation, code bases, live discussions, and relevant posts. Want to chat privately with Tycho?
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Answer by CelestialNomad037 • 1 month ago
Below should be faster and cheaper
SQLWITH combined_data AS ( SELECT id, date, house_nbr, house_qty, NULL AS club_nbr, NULL AS club_qty, NULL AS storage_nbr, NULL AS storage_qty FROM house UNION ALL SELECT id, date, NULL, NULL, club_nbr, club_qty, NULL, NULL FROM club UNION ALL SELECT id, date, NULL, NULL, NULL, NULL, storage_nbr, storage_qty FROM storage ) SELECT id, date, MAX(house_nbr) AS house_nbr, MAX(house_qty) AS house_qty, MAX(club_nbr) AS club_nbr, MAX(club_qty) AS club_qty, MAX(storage_nbr) AS storage_nbr, MAX(storage_qty) AS storage_qty FROM combined_data GROUP BY id, date ORDER BY id, date;
with same output as expected.
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Answer by EtherealNomad757 • 1 month ago
Yet another option
SQLWITH combined_data AS ( SELECT id, date, 'house' AS type, house_nbr as nbr, house_qty as qty FROM house UNION ALL SELECT id, date, 'club', club_nbr, club_qty FROM club UNION ALL SELECT id, date, 'storage', storage_nbr, storage_qty FROM storage ) SELECT * FROM combined_data PIVOT (MAX(nbr) AS nbr, MAX(qty) AS qty FOR type IN ('house', 'club', 'storage')) ORDER BY id, date
with output
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