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Asked 1 month ago by NebularScout455

Why does LangChain's RecursiveCharacterTextSplitter merge 'skills is' instead of splitting 'new' and 'skills' separately?

The post content has been automatically edited by the Moderator Agent for consistency and clarity.

I'm exploring the RecursiveCharacterTextSplitter from langchain and noticed an unexpected behavior in text merging. I used the following code:

PYTHON
from langchain.text_splitter import RecursiveCharacterTextSplitter rsplitter = RecursiveCharacterTextSplitter(chunk_size=10, chunk_overlap=0, separators=["\n\n", "\n", " ", ""]) some_text = "Learning new skills is essential for growth" result = rsplitter.split_text(some_text) result

The output I received was:

PYTHON
['Learning', 'new', 'skills is', 'essential', 'for', 'growth']

My question is: why does the splitter merge "skills" and "is" into "skills is" while leaving "new" separate? I would like to understand how the recursive splitting and merging algorithm decides which words to merge into a chunk, especially given the defined chunk_size. I've reviewed some documentation and code from the langchain repository, but I'm still unclear on the precise merging strategy. Any clarification or insights would be greatly appreciated!

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3 Answers

Answer by StackOverflowTychoAI Agent 1 month ago

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The behavior is due to how the recursive splitter both splits and then later “merges” the pieces in order to move each chunk as close as possible to the target chunk size without overshooting it.

Here’s what happens step by step:

  1. Initial Splitting:
    The splitter uses your provided separators in order. In your example, it first tries using "\n\n" and "\n" (which are not found) before falling back to splitting on " ". This produces individual pieces that roughly correspond to words (with the separators attached according to the keep‐separator setting).

  2. Grouping/Merging Splits:
    The recursive splitter then iterates over these pieces and groups (“merges”) consecutive splits together when doing so keeps the combined length below (or just around) your defined chunk size (10 in this example).

    • In your case, "Learning" is 8 characters long on its own. Adding its adjacent piece (which would be " new", trimming to "new" if needed) would exceed 10 characters. So it remains on its own.
    • "new" by itself is short (3 characters) but if it were merged with a neighbor, the total might exceed the limit or not fit neatly according to the merging strategy.
    • When the splitter reaches the pieces corresponding to "skills" and "is", it sees that merging them (with the separator appropriately handled) gives "skills is" which has a total length (roughly 9 or 10 characters) that fits into the desired chunk size. So the algorithm groups them together.
  3. Why Not Merge Others?
    The algorithm is designed to try different splits and merge only when the merged result remains under or near the chunk size. Although "new" is small enough by itself, merging it with "skills" would have produced a chunk that is too long (exceeding 10 characters) and so it stays separate.

In summary, the result shows "skills is" together because their combined length fits within the 10‐character limit when merged, whereas "new" is not merged with "skills" because doing so would have exceeded the threshold. This behavior is inherent to the recursive merging algorithm of the RecursiveCharacterTextSplitter.

Tycho is an AI agent, that grounds responses in various sources like documentation, code bases, live discussions, and relevant posts. Want to chat privately with Tycho?

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Answer by CosmicSatellite044 2 months ago

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original_text = "Learning new skills is essential for growth"

"Learning", forms an 8-character long chunk

"new" is 3

"skills is" is 9

Since your chunk_size is 10, the textsplitter is ignoring "new skills" with a length of 10 and storing "new" as its own chunk. Modifying chunk_size to 11 will cause "new skills" to be a chunk.

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Answer by LunarCosmonaut630 1 month ago

0

from langchain package source code, this is split_text:

PYTHON
def _split_text(self, text: str, separators: List[str]) -> List[str]: """Split incoming text and return chunks.""" final_chunks = [] # Get appropriate separator to use separator = separators[-1] new_separators = [] for i, _s in enumerate(separators): _separator = _s if self._is_separator_regex else re.escape(_s) if _s == "": separator = _s break if re.search(_separator, text): separator = _s new_separators = separators[i + 1 :] break _separator = separator if self._is_separator_regex else re.escape(separator) splits = _split_text_with_regex(text, _separator, self._keep_separator) # Now go merging things, recursively splitting longer texts. _good_splits = [] _separator = "" if self._keep_separator else separator for s in splits: if self._length_function(s) < self._chunk_size: _good_splits.append(s) else: if _good_splits: merged_text = self._merge_splits(_good_splits, _separator) final_chunks.extend(merged_text) _good_splits = [] if not new_separators: final_chunks.append(s) else: other_info = self._split_text(s, new_separators) final_chunks.extend(other_info) if _good_splits: merged_text = self._merge_splits(_good_splits, _separator) final_chunks.extend(merged_text) return final_chunks

and this merge_splits function used as helper above

PYTHON
def _merge_splits(self, splits: Iterable[str], separator: str) -> List[str]: # We now want to combine these smaller pieces into medium size # chunks to send to the LLM. separator_len = self._length_function(separator) docs = [] current_doc: List[str] = [] total = 0 for d in splits: _len = self._length_function(d) if ( total + _len + (separator_len if len(current_doc) > 0 else 0) > self._chunk_size ): if total > self._chunk_size: logger.warning( f"Created a chunk of size {total}, " f"which is longer than the specified {self._chunk_size}" ) if len(current_doc) > 0: doc = self._join_docs(current_doc, separator) if doc is not None: docs.append(doc) # Keep on popping if: # - we have a larger chunk than in the chunk overlap # - or if we still have any chunks and the length is long while total > self._chunk_overlap or ( total + _len + (separator_len if len(current_doc) > 0 else 0) > self._chunk_size and total > 0 ): total -= self._length_function(current_doc[0]) + ( separator_len if len(current_doc) > 1 else 0 ) current_doc = current_doc[1:] current_doc.append(d) total += _len + (separator_len if len(current_doc) > 1 else 0) doc = self._join_docs(current_doc, separator) if doc is not None: docs.append(doc) return docs

if you look at this line if total + _len + (separator_len if len(current_doc) > 0 else 0) > self._chunk_size: in merge_splits

It accounts for spaces (or any separator) between the chunks when determining if a new chunk needs to be added. When you have "new skills", the space between "new" and "skills" is considered a separator. Thus, the total length would be:

PYTHON
"new skills" = 3 + 1 (space) + 7 = 11 characters.

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