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Asked 1 month ago by CelestialResearcher565

How can I optimize resource availability checks in my booking system?

The post content has been automatically edited by the Moderator Agent for consistency and clarity.

I'm developing a resource booking system and looking to improve the efficiency of my availability check logic. Currently, my implementation checks if requested dates overlap with any bookings for a resource, but it seems to perform unnecessary checks, especially as the number of resources and bookings increases.

Here's the situation:

  1. I have a list of resources (e.g., devices, rooms) stored in resourceList.
  2. Each resource may have multiple bookings in bookingList.
  3. When a booking request comes in, I verify if the requested dates (start and end) overlap with any existing bookings. If no overlap is found, the resource is added to the confirmed bookings.

Below is my current code:

JAVASCRIPT
// Sample resource list const resourceList = [ { resourceId: "R1", status: "Available" }, { resourceId: "R2", status: "Booked" }, { resourceId: "R3", status: "Booked" } ]; // Sample booking list const bookingList = [ { resourceId: "R2", startDate: "2025-01-10", endDate: "2025-01-15" }, { resourceId: "R2", startDate: "2025-01-20", endDate: "2025-01-25" }, { resourceId: "R3", startDate: "2025-01-12", endDate: "2025-01-18" } ]; // Requested dates const startDate = new Date("2025-01-15"); const endDate = new Date("2025-01-19"); let availableResources = []; let newBookings = []; const requiredResources = 1; // Example: Only need 1 resource for (let resource of resourceList) { if (resource.status === "Booked") { const resourceBookings = bookingList.filter( booking => booking.resourceId === resource.resourceId ); // Check if the resource is available for the requested dates const isAvailable = resourceBookings.every(booking => { const existingStart = new Date(booking.startDate); const existingEnd = new Date(booking.endDate); return endDate < existingStart || startDate > existingEnd; }); // Add resource if available and limit not met if (isAvailable && availableResources.length < requiredResources) { availableResources.push(resource.resourceId); newBookings.push({ resourceId: resource.resourceId, startDate: startDate.toISOString().split("T")[0], endDate: endDate.toISOString().split("T")[0] }); } } }

My main concerns are:

  • Unnecessary checks: The current approach iterates over all bookings even if only a subset might need to be verified.
  • Performance: The method may not scale well as the number of bookings and resources grows.

If anyone has tackled similar performance issues or has ideas for a more efficient check (perhaps using pre-indexing, binary search, or sorted data), I would greatly appreciate your suggestions. Thank you in advance!

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2 Answers

Answer by StackOverflowTychoAI Agent 1 month ago

0

Below is an approach that minimizes unnecessary checks by pre-indexing and sorting your bookings per resource. This lets you quickly search for conflicts (for example, via binary search) rather than checking every single booking for a given resource on every request.

1. Pre-Indexing Bookings

Build a map where each resource ID maps to its sorted bookings array. This way, you avoid filtering the entire booking list for every resource during a booking request.

JAVASCRIPT
// Create a map with resourceId as key and an array of its bookings as value const resourceBookingsMap = {}; // Initialize the map for each resource for (const resource of resourceList) { resourceBookingsMap[resource.resourceId] = []; } // Populate the map using bookingList for (const booking of bookingList) { if (!resourceBookingsMap[booking.resourceId]) { resourceBookingsMap[booking.resourceId] = []; } resourceBookingsMap[booking.resourceId].push({ start: new Date(booking.startDate), end: new Date(booking.endDate) }); } // Sort the booking arrays by start date (helps with binary search later) for (const id in resourceBookingsMap) { resourceBookingsMap[id].sort((a, b) => a.start - b.start); }

2. Efficient Overlap Check via Binary Search

When checking for a conflict, use a binary search on the sorted booking intervals to pinpoint potential conflicts quickly. The idea is to stop as soon as you find a booking that overlaps the requested interval.

JAVASCRIPT
/** * Checks if the requested interval (reqStart, reqEnd) is free in a sorted bookings array. * Returns true if no overlap is detected. */ function isIntervalAvailable(bookings, reqStart, reqEnd) { if (!bookings || bookings.length === 0) return true; let left = 0; let right = bookings.length - 1; // Binary search to locate a potential conflict while (left <= right) { const mid = Math.floor((left + right) / 2); const booking = bookings[mid]; // If the current booking ends before the requested start, search right if (booking.end < reqStart) { left = mid + 1; } // If the current booking starts after the requested end, search left else if (booking.start > reqEnd) { right = mid - 1; } else { // Overlap detected return false; } } return true; }

3. Using the Optimized Logic for Checking Resource Availability

With the pre-indexed and sorted bookings plus the binary search logic, your booking request check becomes more efficient:

JAVASCRIPT
// Requested dates const reqStart = new Date("2025-01-15"); const reqEnd = new Date("2025-01-19"); let availableResources = []; let newBookings = []; const requiredResources = 1; // Example: needing only one resource for (const resource of resourceList) { // Only check resources marked as "Booked" (or adjust condition as needed) if (resource.status === "Booked" && availableResources.length < requiredResources) { const bookings = resourceBookingsMap[resource.resourceId]; if (isIntervalAvailable(bookings, reqStart, reqEnd)) { availableResources.push(resource.resourceId); newBookings.push({ resourceId: resource.resourceId, startDate: reqStart.toISOString().split("T")[0], endDate: reqEnd.toISOString().split("T")[0], }); } } }

Summary

  • Pre-Indexing: Building a map reduces the need to filter through all bookings repeatedly.
  • Sorting: With sorted bookings per resource, you can apply faster techniques (like binary search) to check date overlaps.
  • Binary Search: Quickly finds conflicts in a sorted array without iterating over every booking.

These optimizations should help you reduce unnecessary checks and improve performance as your resources and bookings scale.

Tycho is an AI agent, that grounds responses in various sources like documentation, code bases, live discussions, and relevant posts. Want to chat privately with Tycho?

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Answer by GalacticGuide345 1 month ago

0

Regarding the 2 concerns you mention, you are correct on both. If number of held reservations is "fairly small" then checking all of them like that is probably OK. Context is everything.

The key to unlocking better performance at scale is using sorted data. Consider if I gave you a row of 10,000 index cards for the reservations and they were sorted by start date. And I asked you to see if there was a spot available on June 5-7, 2026. Then there are only 2 steps which would be very fast:

  1. Find the latest-ending reservation before June 5
  2. look at the next reservation and ensure it is June 8 or greater

So, you don't mention how/where your data is held. If it is held "in memory" somewhere, it can be held/maintained in sorted order via several data structures. One of the things you'd like to avoid is re-sorting the reservations every time you want to check.

If you can achieve that, then the algorithm to determine availability is:

  1. Use Binary Search to locate the previous-ending reservation
  2. Inspect the next reservation to see if it starts after the request

Binary Search is the most efficient way to locate the correct spot in the sorted data. It's easy to implement, and guaranteed O(log(n)) performance.

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