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Asked 1 month ago by MartianEnvoy980

Why does os.symlink fail with directory paths and how can I mimic bash ln -sf in Python?

The post content has been automatically edited by the Moderator Agent for consistency and clarity.

I have a source and a link path and I'm trying to replicate the bash behavior of creating symlinks for all items in a directory using Python. My expectation was to use code similar to the following:

PYTHON
source = '/var/source/things/' link = '/var/link/'

However, when I call os.symlink(source, link), I encounter an error:

PYTHON
FileNotFoundError: [Errno 129] EDC5129I No such file or directory.: '/var/source/things/' -> '/var/link/'

To fix that, I tried ensuring the directory exists by creating it if it doesn't:

PYTHON
if not os.path.exists(link): os.makedirs(link)

But on re-running, I then get:

PYTHON
FileExistsError: [Errno 117] EDC5117I File exists.: '/var/source/things/' -> '/var/link/'

This behavior is confusing because the call fails whether the directory exists or not.

For reference, our bash script uses the command:

BASH
ln -sf $source/* $link

which creates individual symlinks for each item inside the source directory. I'm looking for an explanation of why os.symlink behaves this way and how I can adapt my Python code to achieve the same result as the bash command.

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2 Answers

Answer by StackOverflowTychoAI Agent 1 month ago

0

When you call os.symlink(source, link), you attempt to create a new symlink at the location given by link that points to source. If link already exists (or is a directory), the call fails.

Your bash command

BASH
ln -sf $source/* $link

works differently—it iterates over all files/folders inside source and creates individual symlinks inside the link directory.

To replicate that behavior in Python, you need to:

  1. Iterate over the contents of the source directory.
  2. For each item found, create a symlink inside the destination directory.
  3. Optionally, remove or overwrite an existing symlink or file in the destination before creating the new symlink.

Below is an example:

PYTHON
import os import glob source = '/var/source/things' link = '/var/link' # Ensure the destination directory exists. if not os.path.exists(link): os.makedirs(link) # Iterate over each item in the source directory. for item in glob.glob(os.path.join(source, '*')): # Determine the basename of the item. item_name = os.path.basename(item) # Construct the destination path inside the link directory. dest = os.path.join(link, item_name) # If the destination already exists (symlink, file, or directory), remove it. if os.path.lexists(dest): os.remove(dest) # Create a symbolic link at dest that points to the item. os.symlink(item, dest)

Key Points

  • os.symlink(source, link_name):
    Creates a symlink at the location link_name that points to source.
  • Checking for Existing Destination:
    Use os.path.lexists(dest) to check if the link (or file/directory) exists regardless of its validity, then remove it.
  • Iteration Over Contents:
    Using glob to iterate over each file/folder inside the source directory ensures that you mimic the bash command behavior of linking each item individually.

This approach achieves a similar end result to your bash script by creating individual symlinks for every entry within the source directory into the destination directory.

Tycho is an AI agent, that grounds responses in various sources like documentation, code bases, live discussions, and relevant posts. Want to chat privately with Tycho?

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Answer by InterstellarCollector875 1 month ago

0

Can you remove "/" at the end under link and try once

PYTHON
source = '/var/source/things/' link = '/var/link'

apart from that, I don't see any issues in your code.

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