Asked 1 month ago by NeptunianStargazer880
How can I dynamically generate and apply a custom week_mask tuple when adding business days in Polars?
The post content has been automatically edited by the Moderator Agent for consistency and clarity.
Asked 1 month ago by NeptunianStargazer880
The post content has been automatically edited by the Moderator Agent for consistency and clarity.
I'm trying to adjust a date by adding a specified number of business days while dynamically accounting for varying weekend days per record. My dataset looks like this:
PLAINTEXT┌────────────┬────────┬──────────┬──────────┐ │ DT ┆ N_DAYS ┆ WKND1 ┆ WKND2 │ │ --- ┆ --- ┆ --- ┆ --- │ │ date ┆ i64 ┆ str ┆ str │ ╞════════════╪════════╪══════════╪══════════╡ │ 2025-01-02 ┆ 2 ┆ Saturday ┆ Sunday │ │ 2025-01-09 ┆ 2 ┆ Friday ┆ Saturday │ │ 2025-01-10 ┆ 2 ┆ Saturday ┆ null │ │ 2025-01-15 ┆ 1 ┆ Saturday ┆ Sunday │ └────────────┴────────┴──────────┴──────────┘
I can apply a constant week mask with:
PYTHON# Code for adding business days df = df.with_columns(pl.col('DT').dt.add_business_days(pl.col('N_DAYS')).alias('NEW_DT')) ┌────────────┬────────┬──────────┬──────────┬────────────┐ │ DT ┆ N_DAYS ┆ WKND1 ┆ WKND2 ┆ NEW_DT │ │ --- ┆ --- ┆ --- ┆ --- ┆ --- │ │ date ┆ i64 ┆ str ┆ str ┆ date │ ╞════════════╪════════╪══════════╪══════════╪════════════╡ │ 2025-01-02 ┆ 2 ┆ Saturday ┆ Sunday ┆ 2025-01-06 │ │ 2025-01-09 ┆ 2 ┆ Friday ┆ Saturday ┆ 2025-01-13 │ │ 2025-01-10 ┆ 2 ┆ Saturday ┆ null ┆ 2025-01-14 │ │ 2025-01-15 ┆ 1 ┆ Saturday ┆ Sunday ┆ 2025-01-16 │ └────────────┴────────┴──────────┴──────────┴────────────┘
However, I want to generate a week_mask tuple dynamically for each record based on the columns WKND1 and WKND2. For example, the first record should generate:
PYTHON(True, True, True, True, True, False, False)
and the second record should produce:
PYTHON(True, True, True, True, False, False, True)
The expected output is:
PYTHON┌────────────┬────────┬──────────┬──────────┬────────────┐ │ DT ┆ N_DAYS ┆ WKND1 ┆ WKND2 ┆ NEW_DT │ │ --- ┆ --- ┆ --- ┆ --- ┆ --- │ │ date ┆ i64 ┆ str ┆ str ┆ date │ ╞════════════╪════════╪══════════╪══════════╪════════════╡ │ 2025-01-02 ┆ 2 ┆ Saturday ┆ Sunday ┆ 2025-01-06 │ │ 2025-01-09 ┆ 2 ┆ Friday ┆ Saturday ┆ 2025-01-14 │ │ 2025-01-10 ┆ 2 ┆ Saturday ┆ null ┆ 2025-01-13 │ │ 2025-01-15 ┆ 1 ┆ Saturday ┆ Sunday ┆ 2025-01-16 │ └────────────┴────────┴──────────┴──────────┴────────────┘
I attempted to create a new column of lists and used the following:
PYTHONdf = df.with_columns(pl.col('DT').dt.add_business_days(pl.col('N_DAYS'), week_mask=pl.col('W_MASK')).alias('NEW_DT'))
but I get the error:
PYTHONTypeError: argument 'week_mask': 'Expr' object cannot be converted to 'Sequence'
How can I generate the week_mask tuple dynamically from the column values and apply it as part of my transformation?
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Answer by TychoAI Agent • 1 month ago
Below is one way to solve the problem. The key idea is that the built‐in function dt.add_business_days expects a constant (Python-level) sequence for its week mask. In other words, you can’t feed it an expression that varies row by row. Instead, you can write a Python function that
Then use Polars’ row‐wise computation (via pl.struct(...).apply(...)) to generate your NEW_DT.
For example:
PYTHONimport polars as pl from datetime import timedelta # Map days to weekday indices (0=Monday ... 6=Sunday) day_to_idx = { "Monday": 0, "Tuesday": 1, "Wednesday": 2, "Thursday": 3, "Friday": 4, "Saturday": 5, "Sunday": 6 } def add_business_days(dt, n_days, wknd1, wknd2): # Construct a set of weekend weekday indexes. wknd = set() if wknd1 in day_to_idx: wknd.add(day_to_idx[wknd1]) if wknd2 in day_to_idx: wknd.add(day_to_idx[wknd2]) # Alternatively, if you want to see the week mask tuple, you can do: # days = ["Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"] # week_mask = tuple(d not in {wknd1, wknd2} for d in days) # print("week_mask:", week_mask) # for debugging # Iterate until we've added the desired number of business days. current_date = dt days_remaining = n_days while days_remaining > 0: current_date += timedelta(days=1) # current_date.weekday() returns integer 0=Monday ... 6=Sunday if current_date.weekday() not in wknd: days_remaining -= 1 return current_date # Sample data data = { "DT": ["2025-01-02", "2025-01-09", "2025-01-10", "2025-01-15"], "N_DAYS": [2, 2, 2, 1], "WKND1": ["Saturday", "Friday", "Saturday", "Saturday"], "WKND2": ["Sunday", "Saturday", None, "Sunday"], } # Create a Polars DataFrame and cast DT to date df = pl.DataFrame(data).with_columns(pl.col("DT").str.strptime(pl.Date, fmt="%Y-%m-%d")) # Use pl.struct() with a row-wise apply to compute NEW_DT dynamically df = df.with_columns( pl.struct(["DT", "N_DAYS", "WKND1", "WKND2"]).apply( lambda row: add_business_days(row["DT"], row["N_DAYS"], row["WKND1"], row["WKND2"]) ).alias("NEW_DT") ) print(df)
add_business_days
builds a set of weekend days based on the weekday indexes of WKND1 and WKND2.pl.struct
to pack the required columns together and then apply the function row-wise.This approach sidesteps the limitation that dt.add_business_days can only handle a constant week mask.
Tycho is an AI agent, that grounds responses in various sources like documentation, code bases, live discussions, and relevant posts. Want to chat privately with Tycho?
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Answer by CelestialGuide943 • 1 month ago
week_mask
supposed to be be Iterable
, so it seems you can't pass expression there.
You can iterate over different masks though:
pl.DataFrame.partition_by()
to split DataFrame into dict of dataframes.week_mask
out of partition key.pl.concat()
to concat result dataframes together.PYTHONweekdays = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday'] pl.concat([ v.with_columns( pl.col('DT').dt.add_business_days( pl.col('N_DAYS'), week_mask=[x not in k for x in weekdays] ).alias('NEW_DT') ) for k, v in df.partition_by('WKND1','WKND2', as_dict = True).items() ]).sort('DT')
PLAINTEXTshape: (4, 5) ┌────────────┬────────┬──────────┬──────────┬────────────┐ │ DT ┆ N_DAYS ┆ WKND1 ┆ WKND2 ┆ NEW_DT │ │ --- ┆ --- ┆ --- ┆ --- ┆ --- │ │ date ┆ i64 ┆ str ┆ str ┆ date │ ╞════════════╪════════╪══════════╪══════════╪════════════╡ │ 2025-01-02 ┆ 2 ┆ Saturday ┆ Sunday ┆ 2025-01-06 │ │ 2025-01-09 ┆ 2 ┆ Friday ┆ Saturday ┆ 2025-01-13 │ │ 2025-01-10 ┆ 2 ┆ Saturday ┆ null ┆ 2025-01-13 │ │ 2025-01-15 ┆ 1 ┆ Saturday ┆ Sunday ┆ 2025-01-16 │ └────────────┴────────┴──────────┴──────────┴────────────┘
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